Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input Specification:
Each input file contains one test case. Each case contains a pair of integers a and b where −10^6^≤a,b≤10^6^ . The numbers are separated by a space.
Output Specification:
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input:
-1000000 9
Sample Output:
-999,991
代码
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
#include <iostream>
using namespace std;
void print(int x) {
if (x / 1000) {
print(x / 1000);
printf(",%03d", x % 1000);
} else
cout << x % 1000;
}
int main() {
int a, b, c;
cin >> a >> b;
c = a + b;
if (c < 0) {
cout << '-';
c = -c;
}
print(c);
return 0;
}
柳神
递归都可用循环写，可惜我不会
1
2
3
4
5
6
7
8
9
10
11
12
13
14
#include <iostream>
using namespace std;
int main() {
int a, b;
cin >> a >> b;
string s = to_string(a + b);
int len = s.length();
for (int i = 0; i < len; i++) {
cout << s[i];
if (s[i] == '-') continue;
if ((i + 1) % 3 == len % 3 && i != len - 1) cout << ",";
}
return 0;
}
